Minimum Operations to Equalize Binary String โ€” Algorithm Visualization & Coding Challenge

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Understanding Minimum Operations to Equalize Binary String
Detailed explanation and reference materials
Problem Overview

๐Ÿ”ฅ Minimum Operations to Equalize Binary String

Difficulty: ๐Ÿ”ด Hard
Topics: โ€ข Greedy โ€ข Parity


๐Ÿง  Problem Statement

You are given:

  • A binary string s
  • An integer k

โš™๏ธ Operation Rule

In one operation, you must:

  • Choose exactly k different indices
  • Flip each selected character:
    • '0' โ†’ '1'
    • '1' โ†’ '0'

๐ŸŽฏ Goal

Return the minimum number of operations required to make all characters equal to '1'.

If it is not possible, return:

-1

๐Ÿ“Œ Example 1

Input

s = "110"
k = 1

Output

1

Explanation

There is one '0' in the string.

Since k = 1, we can flip it directly in one operation.


๐Ÿ“Œ Example 2

Input

s = "0101"
k = 3

Output

2

Explanation

One optimal sequence:

Operation 1:
Flip indices [0, 1, 3]

"0101" โ†’ "1000"

Operation 2:
Flip indices [1, 2, 3]

"1000" โ†’ "1111"

โœ… Minimum operations = 2


๐Ÿ“Œ Example 3

Input

s = "101"
k = 2

Output

-1

Explanation

There is only one '0', but each operation must flip exactly 2 indices.

โš ๏ธ Impossible to make all characters '1'.


๐Ÿ“Š Constraints

  • 1 <= s.length <= 10^5
  • s[i] is either '0' or '1'
  • 1 <= k <= s.length

๐Ÿ’ก Key Insight Hint

Each operation flips exactly k bits.

Think in terms of:

  • Number of zeros
  • Parity (even/odd flips)
  • Mathematical feasibility

๐Ÿ’ป Java Implementation

java
public class Main {

    public static int minimumOperations(String s, int k) {

        int n = s.length();
        int zeroCount = 0;

        // Count number of zeros
        for (int i = 0; i < n; i++) {
            if (s.charAt(i) == '0') {
                zeroCount++;
            }
        }

        // If already all 1s
        if (zeroCount == 0) {
            return 0;
        }

        // Try possible number of operations
        for (int t = 1; t <= n; t++) {

            int totalFlips = t * k;

            // Condition 1: must flip at least all zeros
            if (totalFlips < zeroCount) continue;

            // Condition 2: extra flips must be even
            if ((totalFlips - zeroCount) % 2 == 0) {
                return t;
            }
        }

        return -1;
    }

    public static void main(String[] args) {

        // Hardcoded test cases

        String s1 = "110";
        int k1 = 1;

        String s2 = "0101";
        int k2 = 3;

        String s3 = "101";
        int k3 = 2;
        int ans1 = minimumOperations(s1, k1);
        int ans2 = minimumOperations(s1, k1);
        int ans3 = minimumOperations(s1, k1);
        System.out.println("Example 1 Output: " + ans1);
        System.out.println("Example 2 Output: " + ans2);
        System.out.println("Example 3 Output: " + ans3);
    }
}
โ€” Written by Saurabh Patil โ€ข B.Tech CSE โ€ข Software Developer

Categories
greedy
Parity
leetcode-problem-of-the-day
java
Reference Link
https://leetcode.com/problems/minimum-operations-to-equalize-binary-string/description/

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