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You have n boxes represented as a binary string boxes, where:
'0' means the box is empty.'1' means the box contains one ball.You can move a ball from one box to an adjacent box in one operation. A box is adjacent if the difference in their indices is 1.
You need to calculate an array answer of size n where:
answer[i] is the minimum number of operations required to move all balls to the ith box, considering the initial positions of the balls.Input:
boxes = "110"
Output:
[1, 1, 3]

all balls to the 0th index box from the initial state = 1.
all balls to the 1st index box from the initial state = 1.
all balls to the 3rd index box from the initial state = 2.
total number of operations required to move all balls to each index box from the initial state is given by the array:ans = [1, 1, 3]Explanation:
1 operation.1 operation.2 operations.1 operation.3 operations.Input:
boxes = "001011"
Output:
[11, 8, 5, 4, 3, 4]
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Drag and arrange the algorithm steps in the correct execution order instead of spending time typing code letter by letter.
The algorithm is divided into three logical parts. Carefully rearrange each section in the correct order to form a complete and valid solution.
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