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Given a string s, find the length of the longest substring without repeating characters.
To solve this problem, we can use the sliding window technique along with a dictionary to keep track of the most recent index of each character.
last_position (dictionary): Stores the last seen index of each character.max_length (integer): Tracks the length of the longest substring without repeating characters. Initialize it to 0.prev (integer): Marks the starting index of the current substring window. Initialize it to 0.Use a for loop to iterate over the string with an index i and the current character s[i].
Check for Repeating Characters:
s[i] is found in last_position and last_position[s[i]] >= prev:
prev to last_position[s[i]] + 1 to move the starting index of the window after the last occurrence of the character.Update the Window and Variables:
last_position[s[i]] to the current index i.i - prev + 1.max_length if the current substring length is greater.After the loop, max_length contains the length of the longest substring without repeating characters.
Input:
s = "abcabcbb"
Output:
3
Explanation:
The longest substring without repeating characters is "abc", with a length of 3.
Input:
s = "bbbbb"
Output:
1
Explanation:
The longest substring without repeating characters is "b", with a length of 1.
Input:
s = "pwwkew"
Output:
3
Explanation:
The longest substring without repeating characters is "wke", with a length of 3.
Input:
s = "abcde"
Output:
5
Explanation:
All characters are unique, so the longest substring is the entire string.
Input:
s = ""
Output:
0
Explanation:
The string is empty, so the longest substring length is 0.
Input:
s = "abba"
Output:
2
Explanation:
The longest substrings without repeating characters are "ab" or "ba", both with a length of 2.
0 <= s.length <= 10^5s consists of English letters, digits, symbols, and spaces.🎯 Select Challenge to activate
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The algorithm is divided into three logical parts. Carefully rearrange each section in the correct order to form a complete and valid solution.
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