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Difficulty: Medium Topics: Binary strings, substrings, combinatorics
Condition: A substring has dominant ones if:
#ones >= (#zeros)^2
You are given a binary string s (characters '0' and '1' only).
Return the number of substrings of s that have dominant ones.
A substring has dominant ones if:
Formally:
ones(substring) >= zeros(substring)^2
Input: s = "00011"
Output: 5
Explanation (dominant substrings):
| i | j | s[i..j] | #Zeros | #Ones |
|---|---|---|---|---|
| 3 | 3 | 1 | 0 | 1 |
| 4 | 4 | 1 | 0 | 1 |
| 2 | 3 | 01 | 1 | 1 |
| 3 | 4 | 11 | 0 | 2 |
| 2 | 4 | 011 | 1 | 2 |
Input: s = "101101"
Output: 16
There are 21 total substrings; 5 do not satisfy the inequality, so 16 do.
Non-dominant examples (for clarity):
| i | j | s[i..j] | #Zeros | #Ones |
|---|---|---|---|---|
| 1 | 1 | 0 | 1 | 0 |
| 4 | 4 | 0 | 1 | 0 |
| 1 | 4 | 0110 | 2 | 2 |
| 0 | 4 | 10110 | 2 | 3 |
| 1 | 5 | 01101 | 2 | 3 |
Input:"00011"
Output: 5
Input: "101101"
Output: 16
Happy coding — may your substrings be dominated by ones!
— Written by Saurabh Patil • B.Tech CSE • Software Developer🎯 Select Challenge to activate
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